1/7x^2+1=4/7x

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Solution for 1/7x^2+1=4/7x equation: 



1/7x^2+1=4/7x

We move all terms to the left:

1/7x^2+1-(4/7x)=0



Domain of the equation: 7x^2!=0

x^2!=0/7

x^2!=√0

x!=0

x∈R





Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/7x^2-(+4/7x)+1=0

We get rid of parentheses

1/7x^2-4/7x+1=0

We calculate fractions

We do not support expression: x^3

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